Eikonal Blog

2010.01.05

Number theory finite concidental sums

Filed under: mathematics, number theory — Tags: — sandokan65 @ 15:43

1+3+3^n+3^{n+1}+3^{2n} = (2+3^n)^2

1+3^n+3^{n+1}+3^{2n} +3^{2n+1}= (1+2 \cdot 3^n)^2

1+7+7^2+7^3=20^2

1+12^2+12^3+12^4+12^5=521^2


Reference: T1277


Similar here: More simple math wonders – https://eikonal.wordpress.com/2012/03/14/more-simple-math-wonders/ | Mental calculation of cube root of a six-digit number – https://eikonal.wordpress.com/2010/01/14/mental-calculation-of-cube-root-of-a-two-digit-number/ | Squares with just two different decimal digits – https://eikonal.wordpress.com/2010/01/05/squares-with-just-two-different-decimal-digits/ | Number theory finite concidental sums – https://eikonal.wordpress.com/2010/01/05/number-theory-finite-considental-sums/

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